• Link to new site (under construction).

Papers more recent than the book:

• Matter Universe: Message in the Mathematics - Why the universe is dominated by matter.

• Matter Universe: A Mathematical Solution - Longer version put together for potential publication.

After publication this will be replaced with final version.

• Division Algebras, Clifford Algebras, Periodicity - Toward an order 24 periodicity akin to

the Bott periodicity of order 8.

Papers more recent than the book:

• Matter Universe: Message in the Mathematics - Why the universe is dominated by matter.

• Matter Universe: A Mathematical Solution - Longer version put together for potential publication.

After publication this will be replaced with final version.

• Division Algebras, Clifford Algebras, Periodicity - Toward an order 24 periodicity akin to

the Bott periodicity of order 8.

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**Add To Homescreen,**

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to that end.

it will create an icon on your mobile device,

and thereafter should open without the browser

window. The content has been explicitely coded

to that end.

Entropy: When running, once a cycle (every 0.1s), a single square, chosen randomly, will change from blue to red, or red to blue. What are the odds, once started, all the squares will ever again be all the same color? (Extremely small.) In general, the larger the percentage of one color verses the other, the faster the system will move to a configuration with more equal percentages - that is, greater randomness (increase in entropy is faster for more orderly (low temperature) systems). It's all a matter of probabilities, and when speaking of systems of atoms, whose numbers vastly exceed the hundreds of squares here, the increase in entropy is inexorable. In this simple system of squares, once we get near a 50/50 distribution of blue and red, the odds are very small we will ever again drift far from that, because the vast majority of possible states are near 50/50.

A = 1:0:0:0:0:0:0:0

B = 1:0:0:0:0:0:0:0

C = 1:0:0:0:0:0:0:0

D = 1:0:0:0:0:0:0:0

A(B(CD)) =

1:0:0:0:0:0:0:0

(AB)(CD) =

1:0:0:0:0:0:0:0

A((BC)D) =

1:0:0:0:0:0:0:0

(A(BC))D =

1:0:0:0:0:0:0:0

((AB)C)D =

1:0:0:0:0:0:0:0

Inputs must be of the following form (eight numbers separated by colons):

1:2:3:4:5:6:7:8/2

where the number after the '/' is an overall fractional factor.

They appear in the order: A,B,C,D.